Solve for A
A = \frac{106}{3} = 35\frac{1}{3} \approx 35.333333333
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A≔\frac{106}{3}
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A=\frac{530}{15}
Multiply 500 and 1.06 to get 530.
A=\frac{106}{3}
Reduce the fraction \frac{530}{15} to lowest terms by extracting and canceling out 5.
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