Solve A=-5(x+2)quadB

$$A = - 5 ( x + 2 ) \quad B$$

Solve for B (complex solution)

$$\left\{\begin{matrix}B=-\frac{A}{5\left(x+2\right)}\text{, }&x\neq -2\\B\in \mathrm{C}\text{, }&A=0\text{ and }x=-2\end{matrix}\right.$$

Steps for Solving Linear Equation

Use the distributive property to multiply -5 by x+2.

$$A=\left(-5x-10\right)B$$

Use the distributive property to multiply -5x-10 by B.

$$A=-5xB-10B$$

Swap sides so that all variable terms are on the left hand side.

$$-5xB-10B=A$$

Combine all terms containing B.

$$\left(-5x-10\right)B=A$$

Divide both sides by -5x-10.

$$\frac{\left(-5x-10\right)B}{-5x-10}=\frac{A}{-5x-10}$$

Dividing by -5x-10 undoes the multiplication by -5x-10.

$$B=\frac{A}{-5x-10}$$

Divide A by -5x-10.

$$B=-\frac{A}{5\left(x+2\right)}$$

Solve for A

$$A=-5B\left(x+2\right)$$

Solution Steps

Use the distributive property to multiply -5 by x+2.

$$A=\left(-5x-10\right)B$$

Use the distributive property to multiply -5x-10 by B.

$$A=-5xB-10B$$

Solve for B

$$\left\{\begin{matrix}B=-\frac{A}{5\left(x+2\right)}\text{, }&x\neq -2\\B\in \mathrm{R}\text{, }&A=0\text{ and }x=-2\end{matrix}\right.$$

Steps for Solving Linear Equation

Use the distributive property to multiply -5 by x+2.

$$A=\left(-5x-10\right)B$$

Use the distributive property to multiply -5x-10 by B.

$$A=-5xB-10B$$

Swap sides so that all variable terms are on the left hand side.

$$-5xB-10B=A$$

Combine all terms containing B.

$$\left(-5x-10\right)B=A$$

Divide both sides by -5x-10.

$$\frac{\left(-5x-10\right)B}{-5x-10}=\frac{A}{-5x-10}$$

Dividing by -5x-10 undoes the multiplication by -5x-10.

$$B=\frac{A}{-5x-10}$$

Divide A by -5x-10.

$$B=-\frac{A}{5\left(x+2\right)}$$