Solve A=(1+sqrt{2})^2

$$A = ( 1 + \sqrt { 2 } ) ^ { 2 }$$

Solve for A

$$A=2\sqrt{2}+3\approx 5.828427125$$

Steps for Solving Linear Equation

Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(1+\sqrt{2}\right)^{2}.

$$A=1+2\sqrt{2}+\left(\sqrt{2}\right)^{2}$$

The square of \sqrt{2} is 2.

$$A=1+2\sqrt{2}+2$$

Add 1 and 2 to get 3.

$$A=3+2\sqrt{2}$$

Assign A

$$A≔2\sqrt{2}+3$$