Solve A=(-x-4)^2

$$A = ( - x - 4 ) ^ { 2 }$$

Solve for A

$$A=\left(x+4\right)^{2}$$

Solution Steps

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(-x-4\right)^{2}.

$$A=\left(-x\right)^{2}-8\left(-x\right)+16$$

Calculate -x to the power of 2 and get x^{2}.

$$A=x^{2}-8\left(-x\right)+16$$

Multiply -8 and -1 to get 8.

$$A=x^{2}+8x+16$$

Solve for x (complex solution)

$$x=\sqrt{A}-4$$

$$x=-\sqrt{A}-4$$

Solve for x

$$x=\sqrt{A}-4$$

$$x=-\sqrt{A}-4\text{, }A\geq 0$$