Solve A=(-a^3)^2-B

$$A = ( - a ^ { 3 } ) ^ { 2 } - B$$

Solve for A

$$A=a^{6}-B$$

Solution Steps

Calculate -a^{3} to the power of 2 and get \left(a^{3}\right)^{2}.

$$A=\left(a^{3}\right)^{2}-B$$

To raise a power to another power, multiply the exponents. Multiply 3 and 2 to get 6.

$$A=a^{6}-B$$

Solve for B

$$B=a^{6}-A$$

Steps for Solving Linear Equation

Calculate -a^{3} to the power of 2 and get \left(a^{3}\right)^{2}.

$$A=\left(a^{3}\right)^{2}-B$$

To raise a power to another power, multiply the exponents. Multiply 3 and 2 to get 6.

$$A=a^{6}-B$$

Swap sides so that all variable terms are on the left hand side.

$$a^{6}-B=A$$

Subtract a^{6} from both sides.

$$-B=A-a^{6}$$

Divide both sides by -1.

$$\frac{-B}{-1}=\frac{A-a^{6}}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$B=\frac{A-a^{6}}{-1}$$

Divide -a^{6}+A by -1.

$$B=a^{6}-A$$