Solve A=sqrt{7-2x}

$$A = \sqrt { 7 - 2 x }$$

Solve for x

$$x=\frac{7-A^{2}}{2}$$

$$A\geq 0$$

Steps for Solving Radical Equations

Swap sides so that all variable terms are on the left hand side.

$$\sqrt{7-2x}=A$$

Square both sides of the equation.

$$-2x+7=A^{2}$$

Subtract 7 from both sides of the equation.

$$-2x+7-7=A^{2}-7$$

Subtracting 7 from itself leaves 0.

$$-2x=A^{2}-7$$

Divide both sides by -2.

$$\frac{-2x}{-2}=\frac{A^{2}-7}{-2}$$

Dividing by -2 undoes the multiplication by -2.

$$x=\frac{A^{2}-7}{-2}$$

Divide A^{2}-7 by -2.

$$x=\frac{7-A^{2}}{2}$$

Solve for x (complex solution)

$$x=\frac{7-A^{2}}{2}$$

$$arg(A)<\pi \text{ or }A=0$$

Solve for A

$$A=\sqrt{7-2x}$$

$$x\leq \frac{7}{2}$$