Solve A=pi*(2sqrt{b})^2

$$A = \pi \cdot ( 2 \sqrt { b } ) ^ { 2 }$$

Solve for A

$$A=4\pi b$$

$$b\geq 0$$

Solution Steps

Expand \left(2\sqrt{b}\right)^{2}.

$$A=\pi \times 2^{2}\left(\sqrt{b}\right)^{2}$$

Calculate 2 to the power of 2 and get 4.

$$A=\pi \times 4\left(\sqrt{b}\right)^{2}$$

Calculate \sqrt{b} to the power of 2 and get b.

$$A=\pi \times 4b$$

Solve for b

$$b=\frac{A}{4\pi }$$

$$A\geq 0$$

Steps for Solving Linear Equation

Expand \left(2\sqrt{b}\right)^{2}.

$$A=\pi \times 2^{2}\left(\sqrt{b}\right)^{2}$$

Calculate 2 to the power of 2 and get 4.

$$A=\pi \times 4\left(\sqrt{b}\right)^{2}$$

Calculate \sqrt{b} to the power of 2 and get b.

$$A=\pi \times 4b$$

Swap sides so that all variable terms are on the left hand side.

$$\pi \times 4b=A$$

The equation is in standard form.

$$4\pi b=A$$

Divide both sides by 4\pi .

$$\frac{4\pi b}{4\pi }=\frac{A}{4\pi }$$

Dividing by 4\pi undoes the multiplication by 4\pi .

$$b=\frac{A}{4\pi }$$