Solve A=5/7-4/3div(5+1/3)

$$A = \frac { 5 } { 7 } - \frac { 4 } { 3 } \div ( 5 + \frac { 1 } { 3 } )$$

Solve for A

$$A=\frac{13}{28}\approx 0.464285714$$

Steps for Solving Linear Equation

Convert 5 to fraction \frac{15}{3}.

$$A=\frac{5}{7}-\frac{\frac{4}{3}}{\frac{15}{3}+\frac{1}{3}}$$

Since \frac{15}{3} and \frac{1}{3} have the same denominator, add them by adding their numerators.

$$A=\frac{5}{7}-\frac{\frac{4}{3}}{\frac{15+1}{3}}$$

Add 15 and 1 to get 16.

$$A=\frac{5}{7}-\frac{\frac{4}{3}}{\frac{16}{3}}$$

Divide \frac{4}{3} by \frac{16}{3} by multiplying \frac{4}{3} by the reciprocal of \frac{16}{3}.

$$A=\frac{5}{7}-\frac{4}{3}\times \frac{3}{16}$$

Multiply \frac{4}{3} times \frac{3}{16} by multiplying numerator times numerator and denominator times denominator.

$$A=\frac{5}{7}-\frac{4\times 3}{3\times 16}$$

Cancel out 3 in both numerator and denominator.

$$A=\frac{5}{7}-\frac{4}{16}$$

Reduce the fraction \frac{4}{16} to lowest terms by extracting and canceling out 4.

$$A=\frac{5}{7}-\frac{1}{4}$$

Least common multiple of 7 and 4 is 28. Convert \frac{5}{7} and \frac{1}{4} to fractions with denominator 28.

$$A=\frac{20}{28}-\frac{7}{28}$$

Since \frac{20}{28} and \frac{7}{28} have the same denominator, subtract them by subtracting their numerators.

$$A=\frac{20-7}{28}$$

Subtract 7 from 20 to get 13.

$$A=\frac{13}{28}$$

Assign A

$$A≔\frac{13}{28}$$