Solve A=frac{3i^{4}+i^42-2i^12}{4i^8-i^1428}quadb)

$$A = \frac { 3 i ^ { 4 } + i ^ { 42 } - 2 i ^ { 12 } } { 4 i ^ { 8 } - i ^ { 1428 } } \quad b )$$

Solve for A

$$A=0$$

Steps for Solving Linear Equation

Calculate i to the power of 4 and get 1.

$$A=\frac{3\times 1+i^{42}-2i^{12}}{4i^{8}-i^{1428}}b$$

Multiply 3 and 1 to get 3.

$$A=\frac{3+i^{42}-2i^{12}}{4i^{8}-i^{1428}}b$$

Calculate i to the power of 42 and get -1.

$$A=\frac{3-1-2i^{12}}{4i^{8}-i^{1428}}b$$

Subtract 1 from 3 to get 2.

$$A=\frac{2-2i^{12}}{4i^{8}-i^{1428}}b$$

Calculate i to the power of 12 and get 1.

$$A=\frac{2-2\times 1}{4i^{8}-i^{1428}}b$$

Multiply 2 and 1 to get 2.

$$A=\frac{2-2}{4i^{8}-i^{1428}}b$$

Subtract 2 from 2 to get 0.

$$A=\frac{0}{4i^{8}-i^{1428}}b$$

Calculate i to the power of 8 and get 1.

$$A=\frac{0}{4\times 1-i^{1428}}b$$

Multiply 4 and 1 to get 4.

$$A=\frac{0}{4-i^{1428}}b$$

Calculate i to the power of 1428 and get 1.

$$A=\frac{0}{4-1}b$$

Subtract 1 from 4 to get 3.

$$A=\frac{0}{3}b$$

Zero divided by any non-zero number gives zero.

$$A=0b$$

Anything times zero gives zero.

$$A=0$$

Solve for b

$$b\in \mathrm{C}$$

$$A=0$$