Solve A=1/2h(B+b);A=99,B=6,b=5

$$A = \frac { 1 } { 2 } h ( B + b ) ; A = 99 , B = 6 , b = 5$$

Solve for A, h, B, b

$$A=99$$

$$h=18$$

$$B=6$$

$$b=5$$

Solution Steps

Consider the first equation. Insert the known values of variables into the equation.

$$99=\frac{1}{2}h\left(6+5\right)$$

Add 6 and 5 to get 11.

$$99=\frac{1}{2}h\times 11$$

Multiply \frac{1}{2} and 11 to get \frac{11}{2}.

$$99=\frac{11}{2}h$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{11}{2}h=99$$

Multiply both sides by \frac{2}{11}, the reciprocal of \frac{11}{2}.

$$h=99\times \frac{2}{11}$$

Multiply 99 and \frac{2}{11} to get 18.

$$h=18$$

The system is now solved.

$$A=99 h=18 B=6 b=5$$