Solve A=1/2h(B+b);A=68,B=10,b=7

$$A = \frac { 1 } { 2 } h ( B + b ) ; A = 68 , B = 10 , b = 7$$

Solve for A, h, B, b

$$A=68$$

$$h=8$$

$$B=10$$

$$b=7$$

Solution Steps

Consider the first equation. Insert the known values of variables into the equation.

$$68=\frac{1}{2}h\left(10+7\right)$$

Add 10 and 7 to get 17.

$$68=\frac{1}{2}h\times 17$$

Multiply \frac{1}{2} and 17 to get \frac{17}{2}.

$$68=\frac{17}{2}h$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{17}{2}h=68$$

Multiply both sides by \frac{2}{17}, the reciprocal of \frac{17}{2}.

$$h=68\times \frac{2}{17}$$

Multiply 68 and \frac{2}{17} to get 8.

$$h=8$$

The system is now solved.

$$A=68 h=8 B=10 b=7$$