Solve for A
A=\frac{3B-C+11}{2}
Solve for B
B=\frac{2A+C-11}{3}
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2A-B-B-B+C=11
Combine A and A to get 2A.
2A-2B-B+C=11
Combine -B and -B to get -2B.
2A-3B+C=11
Combine -2B and -B to get -3B.
2A+C=11+3B
Add 3B to both sides.
2A=11+3B-C
Subtract C from both sides.
2A=3B-C+11
The equation is in standard form.
\frac{2A}{2}=\frac{3B-C+11}{2}
Divide both sides by 2.
A=\frac{3B-C+11}{2}
Dividing by 2 undoes the multiplication by 2.
2A-B-B-B+C=11
Combine A and A to get 2A.
2A-2B-B+C=11
Combine -B and -B to get -2B.
2A-3B+C=11
Combine -2B and -B to get -3B.
-3B+C=11-2A
Subtract 2A from both sides.
-3B=11-2A-C
Subtract C from both sides.
-3B=11-C-2A
The equation is in standard form.
\frac{-3B}{-3}=\frac{11-C-2A}{-3}
Divide both sides by -3.
B=\frac{11-C-2A}{-3}
Dividing by -3 undoes the multiplication by -3.
B=\frac{2A+C-11}{3}
Divide 11-2A-C by -3.
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