Solve for C
C=\frac{2b+487}{63}
Solve for b
b=\frac{63C-487}{2}
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512+63C=999+2b
Swap sides so that all variable terms are on the left hand side.
63C=999+2b-512
Subtract 512 from both sides.
63C=487+2b
Subtract 512 from 999 to get 487.
63C=2b+487
The equation is in standard form.
\frac{63C}{63}=\frac{2b+487}{63}
Divide both sides by 63.
C=\frac{2b+487}{63}
Dividing by 63 undoes the multiplication by 63.
2b=512+63C-999
Subtract 999 from both sides.
2b=-487+63C
Subtract 999 from 512 to get -487.
2b=63C-487
The equation is in standard form.
\frac{2b}{2}=\frac{63C-487}{2}
Divide both sides by 2.
b=\frac{63C-487}{2}
Dividing by 2 undoes the multiplication by 2.
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