Solve 98+20div4*6^2-3(3^2*2div3)=

$$98 + 20 \div 4 \cdot 6 ^ { 2 } - 3 ( 3 ^ { 2 } \cdot 2 \div 3 ) =$$

Evaluate

$$260$$

Solution Steps

Divide 20 by 4 to get 5.

$$98+5\times 6^{2}-3\times \frac{3^{2}\times 2}{3}$$

Calculate 6 to the power of 2 and get 36.

$$98+5\times 36-3\times \frac{3^{2}\times 2}{3}$$

Multiply 5 and 36 to get 180.

$$98+180-3\times \frac{3^{2}\times 2}{3}$$

Add 98 and 180 to get 278.

$$278-3\times \frac{3^{2}\times 2}{3}$$

Calculate 3 to the power of 2 and get 9.

$$278-3\times \frac{9\times 2}{3}$$

Multiply 9 and 2 to get 18.

$$278-3\times \frac{18}{3}$$

Divide 18 by 3 to get 6.

$$278-3\times 6$$

Multiply 3 and 6 to get 18.

$$278-18$$

Subtract 18 from 278 to get 260.

$$260$$

Factor

$$2^{2}\times 5\times 13$$