Solve 95y^2+2xy+3=0

$$95 y ^ { 2 } + 2 x y + 3 = 0$$

Solve for x

$$x=-\frac{95y}{2}-\frac{3}{2y}$$

$$y\neq 0$$

Steps for Solving Linear Equation

Subtract 95y^{2} from both sides. Anything subtracted from zero gives its negation.

$$2xy+3=-95y^{2}$$

Subtract 3 from both sides.

$$2xy=-95y^{2}-3$$

The equation is in standard form.

$$2yx=-95y^{2}-3$$

Divide both sides by 2y.

$$\frac{2yx}{2y}=\frac{-95y^{2}-3}{2y}$$

Dividing by 2y undoes the multiplication by 2y.

$$x=\frac{-95y^{2}-3}{2y}$$

Divide -95y^{2}-3 by 2y.

$$x=-\frac{95y}{2}-\frac{3}{2y}$$

Solve for y (complex solution)

$$y=\frac{\sqrt{x^{2}-285}-x}{95}$$

$$y=\frac{-\sqrt{x^{2}-285}-x}{95}$$

Solve for y

$$y=\frac{\sqrt{x^{2}-285}-x}{95}$$

$$y=\frac{-\sqrt{x^{2}-285}-x}{95}\text{, }|x|\geq \sqrt{285}$$