Solve 90-3*7/6+4-3(4-2)

$$90 - 3 * 7 / 6 + 4 - 3 ( 4 - 2 )$$

Evaluate

$$\frac{169}{2}=84.5$$

Solution Steps

Express 3\times \frac{7}{6} as a single fraction.

$$90-\frac{3\times 7}{6}+4-3\left(4-2\right)$$

Multiply 3 and 7 to get 21.

$$90-\frac{21}{6}+4-3\left(4-2\right)$$

Reduce the fraction \frac{21}{6} to lowest terms by extracting and canceling out 3.

$$90-\frac{7}{2}+4-3\left(4-2\right)$$

Convert 90 to fraction \frac{180}{2}.

$$\frac{180}{2}-\frac{7}{2}+4-3\left(4-2\right)$$

Since \frac{180}{2} and \frac{7}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{180-7}{2}+4-3\left(4-2\right)$$

Subtract 7 from 180 to get 173.

$$\frac{173}{2}+4-3\left(4-2\right)$$

Convert 4 to fraction \frac{8}{2}.

$$\frac{173}{2}+\frac{8}{2}-3\left(4-2\right)$$

Since \frac{173}{2} and \frac{8}{2} have the same denominator, add them by adding their numerators.

$$\frac{173+8}{2}-3\left(4-2\right)$$

Add 173 and 8 to get 181.

$$\frac{181}{2}-3\left(4-2\right)$$

Subtract 2 from 4 to get 2.

$$\frac{181}{2}-3\times 2$$

Multiply 3 and 2 to get 6.

$$\frac{181}{2}-6$$

Convert 6 to fraction \frac{12}{2}.

$$\frac{181}{2}-\frac{12}{2}$$

Since \frac{181}{2} and \frac{12}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{181-12}{2}$$

Subtract 12 from 181 to get 169.

$$\frac{169}{2}$$

Factor

$$\frac{13 ^ {2}}{2} = 84\frac{1}{2} = 84.5$$