Solve 9(7/3)+6(-7/3)-7

$$9( \frac{ 7 }{ 3 } )+6(- \frac{ 7 }{ 3 } )-7$$

Evaluate

$$0$$

Solution Steps

Express 9\times \frac{7}{3} as a single fraction.

$$\frac{9\times 7}{3}+6\left(-\frac{7}{3}\right)-7$$

Multiply 9 and 7 to get 63.

$$\frac{63}{3}+6\left(-\frac{7}{3}\right)-7$$

Divide 63 by 3 to get 21.

$$21+6\left(-\frac{7}{3}\right)-7$$

Express 6\left(-\frac{7}{3}\right) as a single fraction.

$$21+\frac{6\left(-7\right)}{3}-7$$

Multiply 6 and -7 to get -42.

$$21+\frac{-42}{3}-7$$

Divide -42 by 3 to get -14.

$$21-14-7$$

Subtract 14 from 21 to get 7.

$$7-7$$

Subtract 7 from 7 to get 0.

$$0$$

Factor

$$0$$