Solve 9+.4xleq0+.7x

$$9+.4x \leq 0+.7x$$

Solve for x

$$x\geq 30$$

Solution Steps

Anything plus zero gives itself.

$$9+0.4x\leq 0.7x$$

Subtract 0.7x from both sides.

$$9+0.4x-0.7x\leq 0$$

Combine 0.4x and -0.7x to get -0.3x.

$$9-0.3x\leq 0$$

Subtract 9 from both sides. Anything subtracted from zero gives its negation.

$$-0.3x\leq -9$$

Divide both sides by -0.3. Since -0.3 is negative, the inequality direction is changed.

$$x\geq \frac{-9}{-0.3}$$

Expand \frac{-9}{-0.3} by multiplying both numerator and the denominator by 10.

$$x\geq \frac{-90}{-3}$$

Divide -90 by -3 to get 30.

$$x\geq 30$$