Solve for a
a=-\frac{5x}{8}+\frac{1}{2}
Solve for x
x=\frac{4-8a}{5}
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4x-8a=9x-4
Swap sides so that all variable terms are on the left hand side.
-8a=9x-4-4x
Subtract 4x from both sides.
-8a=5x-4
Combine 9x and -4x to get 5x.
\frac{-8a}{-8}=\frac{5x-4}{-8}
Divide both sides by -8.
a=\frac{5x-4}{-8}
Dividing by -8 undoes the multiplication by -8.
a=-\frac{5x}{8}+\frac{1}{2}
Divide 5x-4 by -8.
9x-4-4x=-8a
Subtract 4x from both sides.
5x-4=-8a
Combine 9x and -4x to get 5x.
5x=-8a+4
Add 4 to both sides.
5x=4-8a
The equation is in standard form.
\frac{5x}{5}=\frac{4-8a}{5}
Divide both sides by 5.
x=\frac{4-8a}{5}
Dividing by 5 undoes the multiplication by 5.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
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Limits
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