Solve 9x-4+(-x)-(-1)

$$9 x - 4 + ( - x ) - ( - 1 )$$

Evaluate

$$8x-3$$

Solution Steps

The opposite of -1 is 1.

$$9x-4-x+1$$

Add -4 and 1 to get -3.

$$9x-3-x$$

Combine 9x and -x to get 8x.

$$8x-3$$

Differentiate w.r.t. x

$$8$$

Steps Using Derivative Rule for Sum

The opposite of -1 is 1.

$$\frac{\mathrm{d}}{\mathrm{d}x}(9x-4-x+1)$$

Add -4 and 1 to get -3.

$$\frac{\mathrm{d}}{\mathrm{d}x}(9x-3-x)$$

Combine 9x and -x to get 8x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(8x-3)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$8x^{1-1}$$

Subtract 1 from 1.

$$8x^{0}$$

For any term t except 0, t^{0}=1.

$$8\times 1$$

For any term t, t\times 1=t and 1t=t.

$$8$$