Solve for x
x=\frac{y-2z+3}{3}
Solve for y
y=3x+2z-3
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9x+6z=9+3y
Add 3y to both sides.
9x=9+3y-6z
Subtract 6z from both sides.
9x=3y-6z+9
The equation is in standard form.
\frac{9x}{9}=\frac{3y-6z+9}{9}
Divide both sides by 9.
x=\frac{3y-6z+9}{9}
Dividing by 9 undoes the multiplication by 9.
x=\frac{y}{3}-\frac{2z}{3}+1
Divide 9+3y-6z by 9.
-3y+6z=9-9x
Subtract 9x from both sides.
-3y=9-9x-6z
Subtract 6z from both sides.
-3y=9-6z-9x
The equation is in standard form.
\frac{-3y}{-3}=\frac{9-6z-9x}{-3}
Divide both sides by -3.
y=\frac{9-6z-9x}{-3}
Dividing by -3 undoes the multiplication by -3.
y=3x+2z-3
Divide 9-9x-6z by -3.
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Limits
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