Solve for x
x=\frac{19y}{9}+\frac{2}{3}
Solve for y
y=\frac{9x-6}{19}
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9x=6+19y
Add 19y to both sides.
9x=19y+6
The equation is in standard form.
\frac{9x}{9}=\frac{19y+6}{9}
Divide both sides by 9.
x=\frac{19y+6}{9}
Dividing by 9 undoes the multiplication by 9.
x=\frac{19y}{9}+\frac{2}{3}
Divide 6+19y by 9.
-19y=6-9x
Subtract 9x from both sides.
\frac{-19y}{-19}=\frac{6-9x}{-19}
Divide both sides by -19.
y=\frac{6-9x}{-19}
Dividing by -19 undoes the multiplication by -19.
y=\frac{9x-6}{19}
Divide 6-9x by -19.
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