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9x^{2}+81x=0
Use the distributive property to multiply 9x by x+9.
x\left(9x+81\right)=0
Factor out x.
x=0 x=-9
To find equation solutions, solve x=0 and 9x+81=0.
9x^{2}+81x=0
Use the distributive property to multiply 9x by x+9.
x=\frac{-81±\sqrt{81^{2}}}{2\times 9}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 9 for a, 81 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-81±81}{2\times 9}
Take the square root of 81^{2}.
x=\frac{-81±81}{18}
Multiply 2 times 9.
x=\frac{0}{18}
Now solve the equation x=\frac{-81±81}{18} when ± is plus. Add -81 to 81.
x=0
Divide 0 by 18.
x=-\frac{162}{18}
Now solve the equation x=\frac{-81±81}{18} when ± is minus. Subtract 81 from -81.
x=-9
Divide -162 by 18.
x=0 x=-9
The equation is now solved.
9x^{2}+81x=0
Use the distributive property to multiply 9x by x+9.
\frac{9x^{2}+81x}{9}=\frac{0}{9}
Divide both sides by 9.
x^{2}+\frac{81}{9}x=\frac{0}{9}
Dividing by 9 undoes the multiplication by 9.
x^{2}+9x=\frac{0}{9}
Divide 81 by 9.
x^{2}+9x=0
Divide 0 by 9.
x^{2}+9x+\left(\frac{9}{2}\right)^{2}=\left(\frac{9}{2}\right)^{2}
Divide 9, the coefficient of the x term, by 2 to get \frac{9}{2}. Then add the square of \frac{9}{2} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+9x+\frac{81}{4}=\frac{81}{4}
Square \frac{9}{2} by squaring both the numerator and the denominator of the fraction.
\left(x+\frac{9}{2}\right)^{2}=\frac{81}{4}
Factor x^{2}+9x+\frac{81}{4}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+\frac{9}{2}\right)^{2}}=\sqrt{\frac{81}{4}}
Take the square root of both sides of the equation.
x+\frac{9}{2}=\frac{9}{2} x+\frac{9}{2}=-\frac{9}{2}
Simplify.
x=0 x=-9
Subtract \frac{9}{2} from both sides of the equation.