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x^{2}=\frac{4}{9}
Divide both sides by 9.
x^{2}-\frac{4}{9}=0
Subtract \frac{4}{9} from both sides.
9x^{2}-4=0
Multiply both sides by 9.
\left(3x-2\right)\left(3x+2\right)=0
Consider 9x^{2}-4. Rewrite 9x^{2}-4 as \left(3x\right)^{2}-2^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
x=\frac{2}{3} x=-\frac{2}{3}
To find equation solutions, solve 3x-2=0 and 3x+2=0.
x^{2}=\frac{4}{9}
Divide both sides by 9.
x=\frac{2}{3} x=-\frac{2}{3}
Take the square root of both sides of the equation.
x^{2}=\frac{4}{9}
Divide both sides by 9.
x^{2}-\frac{4}{9}=0
Subtract \frac{4}{9} from both sides.
x=\frac{0±\sqrt{0^{2}-4\left(-\frac{4}{9}\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -\frac{4}{9} for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\left(-\frac{4}{9}\right)}}{2}
Square 0.
x=\frac{0±\sqrt{\frac{16}{9}}}{2}
Multiply -4 times -\frac{4}{9}.
x=\frac{0±\frac{4}{3}}{2}
Take the square root of \frac{16}{9}.
x=\frac{2}{3}
Now solve the equation x=\frac{0±\frac{4}{3}}{2} when ± is plus.
x=-\frac{2}{3}
Now solve the equation x=\frac{0±\frac{4}{3}}{2} when ± is minus.
x=\frac{2}{3} x=-\frac{2}{3}
The equation is now solved.