Solve 9x^2+8y-1=0

$$9 x ^ { 2 } + 8 y - 1 = 0$$

Solve for y

$$y=\frac{1-9x^{2}}{8}$$

Steps for Solving Linear Equation

Subtract 9x^{2} from both sides. Anything subtracted from zero gives its negation.

$$8y-1=-9x^{2}$$

Add 1 to both sides.

$$8y=-9x^{2}+1$$

The equation is in standard form.

$$8y=1-9x^{2}$$

Divide both sides by 8.

$$\frac{8y}{8}=\frac{1-9x^{2}}{8}$$

Dividing by 8 undoes the multiplication by 8.

$$y=\frac{1-9x^{2}}{8}$$

Solve for x (complex solution)

$$x=-\frac{\sqrt{1-8y}}{3}$$

$$x=\frac{\sqrt{1-8y}}{3}$$

Solve for x

$$x=\frac{\sqrt{1-8y}}{3}$$

$$x=-\frac{\sqrt{1-8y}}{3}\text{, }y\leq \frac{1}{8}$$