Solve for x
x=\frac{2z}{9}-\frac{5y}{9}+\frac{4}{3}
Solve for y
y=\frac{12+2z-9x}{5}
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9x-2z=12-5y
Subtract 5y from both sides.
9x=12-5y+2z
Add 2z to both sides.
9x=12+2z-5y
The equation is in standard form.
\frac{9x}{9}=\frac{12+2z-5y}{9}
Divide both sides by 9.
x=\frac{12+2z-5y}{9}
Dividing by 9 undoes the multiplication by 9.
x=\frac{2z}{9}-\frac{5y}{9}+\frac{4}{3}
Divide 12-5y+2z by 9.
5y-2z=12-9x
Subtract 9x from both sides.
5y=12-9x+2z
Add 2z to both sides.
5y=12+2z-9x
The equation is in standard form.
\frac{5y}{5}=\frac{12+2z-9x}{5}
Divide both sides by 5.
y=\frac{12+2z-9x}{5}
Dividing by 5 undoes the multiplication by 5.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
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Limits
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