Solve for x
x=-\frac{10y}{3}
Solve for y
y=-\frac{3x}{10}
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9x=10y-40y
Subtract 40y from both sides.
9x=-30y
Combine 10y and -40y to get -30y.
\frac{9x}{9}=-\frac{30y}{9}
Divide both sides by 9.
x=-\frac{30y}{9}
Dividing by 9 undoes the multiplication by 9.
x=-\frac{10y}{3}
Divide -30y by 9.
9x+40y-10y=0
Subtract 10y from both sides.
9x+30y=0
Combine 40y and -10y to get 30y.
30y=-9x
Subtract 9x from both sides. Anything subtracted from zero gives its negation.
\frac{30y}{30}=-\frac{9x}{30}
Divide both sides by 30.
y=-\frac{9x}{30}
Dividing by 30 undoes the multiplication by 30.
y=-\frac{3x}{10}
Divide -9x by 30.
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