Solve 9k-11+2k-7-4k

$$9 k - 11 + 2 k - 7 - 4 k$$

Evaluate

$$7k-18$$

Solution Steps

Combine 9k and 2k to get 11k.

$$11k-11-7-4k$$

Subtract 7 from -11 to get -18.

$$11k-18-4k$$

Combine 11k and -4k to get 7k.

$$7k-18$$

Differentiate w.r.t. k

$$7$$

Steps Using Derivative Rule for Sum

Combine 9k and 2k to get 11k.

$$\frac{\mathrm{d}}{\mathrm{d}k}(11k-11-7-4k)$$

Subtract 7 from -11 to get -18.

$$\frac{\mathrm{d}}{\mathrm{d}k}(11k-18-4k)$$

Combine 11k and -4k to get 7k.

$$\frac{\mathrm{d}}{\mathrm{d}k}(7k-18)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$7k^{1-1}$$

Subtract 1 from 1.

$$7k^{0}$$

For any term t except 0, t^{0}=1.

$$7\times 1$$

For any term t, t\times 1=t and 1t=t.

$$7$$