Solve 9g^3+12=3(3g^3+4)

$$9 g ^ { 3 } + 12 = 3 ( 3 g ^ { 3 } + 4 )$$

Solve for g (complex solution)

$$g\in \mathrm{C}$$

Solution Steps

Use the distributive property to multiply 3 by 3g^{3}+4.

$$9g^{3}+12=9g^{3}+12$$

Subtract 9g^{3} from both sides.

$$9g^{3}+12-9g^{3}=12$$

Combine 9g^{3} and -9g^{3} to get 0.

$$12=12$$

Compare 12 and 12.

$$\text{true}$$

This is true for any g.

$$g\in \mathrm{C}$$

Solve for g

$$g\in \mathrm{R}$$

Solution Steps

Use the distributive property to multiply 3 by 3g^{3}+4.

$$9g^{3}+12=9g^{3}+12$$

Subtract 9g^{3} from both sides.

$$9g^{3}+12-9g^{3}=12$$

Combine 9g^{3} and -9g^{3} to get 0.

$$12=12$$

Compare 12 and 12.

$$\text{true}$$

This is true for any g.

$$g\in \mathrm{R}$$