Solve 9b+(-18)-3b+11

$$9 b + ( - 18 ) - 3 b + 11$$

Evaluate

$$6b-7$$

Solution Steps

Combine 9b and -3b to get 6b.

$$6b-18+11$$

Add -18 and 11 to get -7.

$$6b-7$$

Differentiate w.r.t. b

$$6$$

Steps Using Derivative Rule for Sum

Combine 9b and -3b to get 6b.

$$\frac{\mathrm{d}}{\mathrm{d}b}(6b-18+11)$$

Add -18 and 11 to get -7.

$$\frac{\mathrm{d}}{\mathrm{d}b}(6b-7)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$6b^{1-1}$$

Subtract 1 from 1.

$$6b^{0}$$

For any term t except 0, t^{0}=1.

$$6\times 1$$

For any term t, t\times 1=t and 1t=t.

$$6$$