Solve for a
a=\frac{2-c-2b}{9}
Solve for b
b=-\frac{c}{2}-\frac{9a}{2}+1
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9a+c=2-2b
Subtract 2b from both sides.
9a=2-2b-c
Subtract c from both sides.
9a=2-c-2b
The equation is in standard form.
\frac{9a}{9}=\frac{2-c-2b}{9}
Divide both sides by 9.
a=\frac{2-c-2b}{9}
Dividing by 9 undoes the multiplication by 9.
2b+c=2-9a
Subtract 9a from both sides.
2b=2-9a-c
Subtract c from both sides.
2b=2-c-9a
The equation is in standard form.
\frac{2b}{2}=\frac{2-c-9a}{2}
Divide both sides by 2.
b=\frac{2-c-9a}{2}
Dividing by 2 undoes the multiplication by 2.
b=-\frac{c}{2}-\frac{9a}{2}+1
Divide 2-9a-c by 2.
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