Solve for y
\left\{\begin{matrix}y=\frac{9-c}{z}\text{, }&z\neq 0\\y\in \mathrm{R}\text{, }&c=9\text{ and }z=0\end{matrix}\right.
Solve for c
c=9-yz
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-yz=c-9
Subtract 9 from both sides.
\left(-z\right)y=c-9
The equation is in standard form.
\frac{\left(-z\right)y}{-z}=\frac{c-9}{-z}
Divide both sides by -z.
y=\frac{c-9}{-z}
Dividing by -z undoes the multiplication by -z.
y=-\frac{c-9}{z}
Divide c-9 by -z.
c=9-yz
Swap sides so that all variable terms are on the left hand side.
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