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\left(-1+3x-z^{2}\right)\left(-1+3x+z^{2}\right)
Rewrite 9x^{2}-6x+1-z^{4} as \left(-1+3x\right)^{2}-\left(z^{2}\right)^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
\left(3x-z^{2}-1\right)\left(3x+z^{2}-1\right)
Reorder the terms.