Solve 9sqrt{2}3sqrt{2}=27*2=54

$$9 \sqrt{ 2 } 3 \sqrt{ 2 } = 27 \cdot 2=54$$

Verify

Solution Steps

Multiply \sqrt{2} and \sqrt{2} to get 2.

$$3\times 9\times 2=27\times 2\text{ and }27\times 2=54$$

Multiply 3 and 9 to get 27.

$$27\times 2=27\times 2\text{ and }27\times 2=54$$

Multiply 27 and 2 to get 54.

$$54=27\times 2\text{ and }27\times 2=54$$

Multiply 27 and 2 to get 54.

$$54=54\text{ and }27\times 2=54$$

Compare 54 and 54.

$$\text{true}\text{ and }27\times 2=54$$

Multiply 27 and 2 to get 54.

$$\text{true}\text{ and }54=54$$

Compare 54 and 54.

$$\text{true}\text{ and }\text{true}$$

The conjunction of \text{true} and \text{true} is \text{true}.

$$\text{true}$$