Solve 93/3div(1/6+1/8)quad1/11

$$9 \frac { 3 } { 3 } \div ( \frac { 1 } { 6 } + \frac { 1 } { 8 } ) \quad \frac { 1 } { 11 }$$

Evaluate

$$\frac{240}{77}\approx 3.116883117$$

Solution Steps

Multiply 9 and 3 to get 27.

$$\frac{\frac{27+3}{3}}{\frac{1}{6}+\frac{1}{8}}\times \frac{1}{11}$$

Add 27 and 3 to get 30.

$$\frac{\frac{30}{3}}{\frac{1}{6}+\frac{1}{8}}\times \frac{1}{11}$$

Divide 30 by 3 to get 10.

$$\frac{10}{\frac{1}{6}+\frac{1}{8}}\times \frac{1}{11}$$

Least common multiple of 6 and 8 is 24. Convert \frac{1}{6} and \frac{1}{8} to fractions with denominator 24.

$$\frac{10}{\frac{4}{24}+\frac{3}{24}}\times \frac{1}{11}$$

Since \frac{4}{24} and \frac{3}{24} have the same denominator, add them by adding their numerators.

$$\frac{10}{\frac{4+3}{24}}\times \frac{1}{11}$$

Add 4 and 3 to get 7.

$$\frac{10}{\frac{7}{24}}\times \frac{1}{11}$$

Divide 10 by \frac{7}{24} by multiplying 10 by the reciprocal of \frac{7}{24}.

$$10\times \frac{24}{7}\times \frac{1}{11}$$

Express 10\times \frac{24}{7} as a single fraction.

$$\frac{10\times 24}{7}\times \frac{1}{11}$$

Multiply 10 and 24 to get 240.

$$\frac{240}{7}\times \frac{1}{11}$$

Multiply \frac{240}{7} times \frac{1}{11} by multiplying numerator times numerator and denominator times denominator.

$$\frac{240\times 1}{7\times 11}$$

Do the multiplications in the fraction \frac{240\times 1}{7\times 11}.

$$\frac{240}{77}$$

Factor

$$\frac{2 ^ {4} \cdot 3 \cdot 5}{7 \cdot 11} = 3\frac{9}{77} = 3.116883116883117$$