Solve 92/3*27geq71/6*36

$$9 \frac { 2 } { 3 } \times 27 \geq 7 \frac { 1 } { 6 } \times 36$$

Verify

Solution Steps

Multiply both sides of the equation by 6, the least common multiple of 3,6. Since 6 is positive, the inequality direction remains the same.

$$2\left(9\times 3+2\right)\times 27\geq \left(7\times 6+1\right)\times 36$$

Multiply 9 and 3 to get 27.

$$2\left(27+2\right)\times 27\geq \left(7\times 6+1\right)\times 36$$

Add 27 and 2 to get 29.

$$2\times 29\times 27\geq \left(7\times 6+1\right)\times 36$$

Multiply 2 and 29 to get 58.

$$58\times 27\geq \left(7\times 6+1\right)\times 36$$

Multiply 58 and 27 to get 1566.

$$1566\geq \left(7\times 6+1\right)\times 36$$

Multiply 7 and 6 to get 42.

$$1566\geq \left(42+1\right)\times 36$$

Add 42 and 1 to get 43.

$$1566\geq 43\times 36$$

Multiply 43 and 36 to get 1548.

$$1566\geq 1548$$

Compare 1566 and 1548.

$$\text{true}$$