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\frac{\left(9\times 3+2\right)\times 3}{3\left(1\times 3+2\right)}
Divide \frac{9\times 3+2}{3} by \frac{1\times 3+2}{3} by multiplying \frac{9\times 3+2}{3} by the reciprocal of \frac{1\times 3+2}{3}.
\frac{2+3\times 9}{2+3}
Cancel out 3 in both numerator and denominator.
\frac{2+27}{2+3}
Multiply 3 and 9 to get 27.
\frac{29}{2+3}
Add 2 and 27 to get 29.
\frac{29}{5}
Add 2 and 3 to get 5.