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\frac{9}{100}+x=\frac{25\times 4}{100\left(1\times 4+1\right)}
Divide \frac{25}{100} by \frac{1\times 4+1}{4} by multiplying \frac{25}{100} by the reciprocal of \frac{1\times 4+1}{4}.
\frac{9}{100}+x=\frac{1}{1+4}
Cancel out 4\times 25 in both numerator and denominator.
\frac{9}{100}+x=\frac{1}{5}
Add 1 and 4 to get 5.
x=\frac{1}{5}-\frac{9}{100}
Subtract \frac{9}{100} from both sides.
x=\frac{20}{100}-\frac{9}{100}
Least common multiple of 5 and 100 is 100. Convert \frac{1}{5} and \frac{9}{100} to fractions with denominator 100.
x=\frac{20-9}{100}
Since \frac{20}{100} and \frac{9}{100} have the same denominator, subtract them by subtracting their numerators.
x=\frac{11}{100}
Subtract 9 from 20 to get 11.