Solve 9=12z-29/6x

$$9 = \frac { 12 z - 29 } { 6 x }$$

Solve for x

$$x=\frac{2z}{9}-\frac{29}{54}$$

$$z\neq \frac{29}{12}$$

Steps for Solving Linear Equation

Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 6x.

$$54x=12z-29$$

Divide both sides by 54.

$$\frac{54x}{54}=\frac{12z-29}{54}$$

Dividing by 54 undoes the multiplication by 54.

$$x=\frac{12z-29}{54}$$

Divide 12z-29 by 54.

$$x=\frac{2z}{9}-\frac{29}{54}$$

Variable x cannot be equal to 0.

$$x=\frac{2z}{9}-\frac{29}{54}\text{, }x\neq 0$$

Solve for z

$$z=\frac{9x}{2}+\frac{29}{12}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 6x.

$$54x=12z-29$$

Swap sides so that all variable terms are on the left hand side.

$$12z-29=54x$$

Add 29 to both sides.

$$12z=54x+29$$

Divide both sides by 12.

$$\frac{12z}{12}=\frac{54x+29}{12}$$

Dividing by 12 undoes the multiplication by 12.

$$z=\frac{54x+29}{12}$$

Divide 54x+29 by 12.

$$z=\frac{9x}{2}+\frac{29}{12}$$