Solve 9(20*10^-8)*(02*10^-4)

$$9 ( 20 \times 10 ^ { - 8 } ) \times ( 02 \times 10 ^ { - 4 } )$$

Evaluate

$$0$$

Solution Steps

To multiply powers of the same base, add their exponents. Add -8 and -4 to get -12.

$$9\times 20\times 10^{-12}\times 0\times 2$$

Multiply 9 and 20 to get 180.

$$180\times 10^{-12}\times 0\times 2$$

Calculate 10 to the power of -12 and get \frac{1}{1000000000000}.

$$180\times \frac{1}{1000000000000}\times 0\times 2$$

Multiply 180 and \frac{1}{1000000000000} to get \frac{9}{50000000000}.

$$\frac{9}{50000000000}\times 0\times 2$$

Multiply \frac{9}{50000000000} and 0 to get 0.

$$0\times 2$$

Multiply 0 and 2 to get 0.

$$0$$

Factor

$$0$$