Solve for x
x=\frac{y-3}{2}
Solve for y
y=2x+3
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8x=-12+4y
Add 4y to both sides.
8x=4y-12
The equation is in standard form.
\frac{8x}{8}=\frac{4y-12}{8}
Divide both sides by 8.
x=\frac{4y-12}{8}
Dividing by 8 undoes the multiplication by 8.
x=\frac{y-3}{2}
Divide -12+4y by 8.
-4y=-12-8x
Subtract 8x from both sides.
-4y=-8x-12
The equation is in standard form.
\frac{-4y}{-4}=\frac{-8x-12}{-4}
Divide both sides by -4.
y=\frac{-8x-12}{-4}
Dividing by -4 undoes the multiplication by -4.
y=2x+3
Divide -12-8x by -4.
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