Solve for x
x=\frac{3y-z+23}{8}
Solve for y
y=\frac{8x+z-23}{3}
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8x+z=23+3y
Add 3y to both sides.
8x=23+3y-z
Subtract z from both sides.
8x=3y-z+23
The equation is in standard form.
\frac{8x}{8}=\frac{3y-z+23}{8}
Divide both sides by 8.
x=\frac{3y-z+23}{8}
Dividing by 8 undoes the multiplication by 8.
-3y+z=23-8x
Subtract 8x from both sides.
-3y=23-8x-z
Subtract z from both sides.
-3y=23-z-8x
The equation is in standard form.
\frac{-3y}{-3}=\frac{23-z-8x}{-3}
Divide both sides by -3.
y=\frac{23-z-8x}{-3}
Dividing by -3 undoes the multiplication by -3.
y=\frac{8x+z-23}{3}
Divide 23-8x-z by -3.
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