Solve for x
x=-\frac{y}{2}-\frac{3z}{8}
Solve for y
y=-\frac{3z}{4}-2x
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8x+3z=-4y
Subtract 4y from both sides. Anything subtracted from zero gives its negation.
8x=-4y-3z
Subtract 3z from both sides.
\frac{8x}{8}=\frac{-4y-3z}{8}
Divide both sides by 8.
x=\frac{-4y-3z}{8}
Dividing by 8 undoes the multiplication by 8.
x=-\frac{y}{2}-\frac{3z}{8}
Divide -4y-3z by 8.
4y+3z=-8x
Subtract 8x from both sides. Anything subtracted from zero gives its negation.
4y=-8x-3z
Subtract 3z from both sides.
\frac{4y}{4}=\frac{-8x-3z}{4}
Divide both sides by 4.
y=\frac{-8x-3z}{4}
Dividing by 4 undoes the multiplication by 4.
y=-\frac{3z}{4}-2x
Divide -8x-3z by 4.
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