Solve 8x+47-98=

$$8x+47-98=$$

Differentiate w.r.t. x

$$8$$

Steps Using Derivative Rule for Sum

Subtract 98 from 47 to get -51.

$$\frac{\mathrm{d}}{\mathrm{d}x}(8x-51)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$8x^{1-1}$$

Subtract 1 from 1.

$$8x^{0}$$

For any term t except 0, t^{0}=1.

$$8\times 1$$

For any term t, t\times 1=t and 1t=t.

$$8$$

Evaluate

$$8x-51$$

Solution Steps

Subtract 98 from 47 to get -51.

$$8x-51$$