Skip to main content
Solve for t
Tick mark Image

Similar Problems from Web Search

Share

-16t^{2}+151t=88
Swap sides so that all variable terms are on the left hand side.
-16t^{2}+151t-88=0
Subtract 88 from both sides.
t=\frac{-151±\sqrt{151^{2}-4\left(-16\right)\left(-88\right)}}{2\left(-16\right)}
This equation is in standard form: ax^{2}+bx+c=0. Substitute -16 for a, 151 for b, and -88 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
t=\frac{-151±\sqrt{22801-4\left(-16\right)\left(-88\right)}}{2\left(-16\right)}
Square 151.
t=\frac{-151±\sqrt{22801+64\left(-88\right)}}{2\left(-16\right)}
Multiply -4 times -16.
t=\frac{-151±\sqrt{22801-5632}}{2\left(-16\right)}
Multiply 64 times -88.
t=\frac{-151±\sqrt{17169}}{2\left(-16\right)}
Add 22801 to -5632.
t=\frac{-151±\sqrt{17169}}{-32}
Multiply 2 times -16.
t=\frac{\sqrt{17169}-151}{-32}
Now solve the equation t=\frac{-151±\sqrt{17169}}{-32} when ± is plus. Add -151 to \sqrt{17169}.
t=\frac{151-\sqrt{17169}}{32}
Divide -151+\sqrt{17169} by -32.
t=\frac{-\sqrt{17169}-151}{-32}
Now solve the equation t=\frac{-151±\sqrt{17169}}{-32} when ± is minus. Subtract \sqrt{17169} from -151.
t=\frac{\sqrt{17169}+151}{32}
Divide -151-\sqrt{17169} by -32.
t=\frac{151-\sqrt{17169}}{32} t=\frac{\sqrt{17169}+151}{32}
The equation is now solved.
-16t^{2}+151t=88
Swap sides so that all variable terms are on the left hand side.
\frac{-16t^{2}+151t}{-16}=\frac{88}{-16}
Divide both sides by -16.
t^{2}+\frac{151}{-16}t=\frac{88}{-16}
Dividing by -16 undoes the multiplication by -16.
t^{2}-\frac{151}{16}t=\frac{88}{-16}
Divide 151 by -16.
t^{2}-\frac{151}{16}t=-\frac{11}{2}
Reduce the fraction \frac{88}{-16} to lowest terms by extracting and canceling out 8.
t^{2}-\frac{151}{16}t+\left(-\frac{151}{32}\right)^{2}=-\frac{11}{2}+\left(-\frac{151}{32}\right)^{2}
Divide -\frac{151}{16}, the coefficient of the x term, by 2 to get -\frac{151}{32}. Then add the square of -\frac{151}{32} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
t^{2}-\frac{151}{16}t+\frac{22801}{1024}=-\frac{11}{2}+\frac{22801}{1024}
Square -\frac{151}{32} by squaring both the numerator and the denominator of the fraction.
t^{2}-\frac{151}{16}t+\frac{22801}{1024}=\frac{17169}{1024}
Add -\frac{11}{2} to \frac{22801}{1024} by finding a common denominator and adding the numerators. Then reduce the fraction to lowest terms if possible.
\left(t-\frac{151}{32}\right)^{2}=\frac{17169}{1024}
Factor t^{2}-\frac{151}{16}t+\frac{22801}{1024}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(t-\frac{151}{32}\right)^{2}}=\sqrt{\frac{17169}{1024}}
Take the square root of both sides of the equation.
t-\frac{151}{32}=\frac{\sqrt{17169}}{32} t-\frac{151}{32}=-\frac{\sqrt{17169}}{32}
Simplify.
t=\frac{\sqrt{17169}+151}{32} t=\frac{151-\sqrt{17169}}{32}
Add \frac{151}{32} to both sides of the equation.