Solve 84*01+3*(-4*025+3^2)+41div2

$$84 \cdot 01 + 3 \cdot ( - 4 \cdot 025 + 3 ^ { 2 } ) + 41 \div 2$$

Evaluate

$$\frac{95}{2}=47.5$$

Solution Steps

Multiply 84 and 0 to get 0.

$$0\times 1+3\left(-4\times 0\times 25+3^{2}\right)+\frac{41}{2}$$

Multiply 0 and 1 to get 0.

$$0+3\left(-4\times 0\times 25+3^{2}\right)+\frac{41}{2}$$

Multiply -4 and 0 to get 0.

$$0+3\left(0\times 25+3^{2}\right)+\frac{41}{2}$$

Multiply 0 and 25 to get 0.

$$0+3\left(0+3^{2}\right)+\frac{41}{2}$$

Calculate 3 to the power of 2 and get 9.

$$0+3\left(0+9\right)+\frac{41}{2}$$

Add 0 and 9 to get 9.

$$0+3\times 9+\frac{41}{2}$$

Multiply 3 and 9 to get 27.

$$0+27+\frac{41}{2}$$

Add 0 and 27 to get 27.

$$27+\frac{41}{2}$$

Convert 27 to fraction \frac{54}{2}.

$$\frac{54}{2}+\frac{41}{2}$$

Since \frac{54}{2} and \frac{41}{2} have the same denominator, add them by adding their numerators.

$$\frac{54+41}{2}$$

Add 54 and 41 to get 95.

$$\frac{95}{2}$$

Factor

$$\frac{5 \cdot 19}{2} = 47\frac{1}{2} = 47.5$$