Factor
3\left(3a-b\right)\left(9a^{2}+3ab+b^{2}\right)
Evaluate
81a^{3}-3b^{3}
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3\left(27a^{3}-b^{3}\right)
Factor out 3.
\left(3a-b\right)\left(9a^{2}+3ab+b^{2}\right)
Consider 27a^{3}-b^{3}. Rewrite 27a^{3}-b^{3} as \left(3a\right)^{3}-b^{3}. The difference of cubes can be factored using the rule: p^{3}-q^{3}=\left(p-q\right)\left(p^{2}+pq+q^{2}\right).
3\left(3a-b\right)\left(9a^{2}+3ab+b^{2}\right)
Rewrite the complete factored expression.
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