Solve for y
y=\frac{81}{7z}
z\neq 0
Solve for z
z=\frac{81}{7y}
y\neq 0
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\frac{81}{y}=7z
Multiply both sides of the equation by z.
81=7zy
Variable y cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by y.
7zy=81
Swap sides so that all variable terms are on the left hand side.
\frac{7zy}{7z}=\frac{81}{7z}
Divide both sides by 7z.
y=\frac{81}{7z}
Dividing by 7z undoes the multiplication by 7z.
y=\frac{81}{7z}\text{, }y\neq 0
Variable y cannot be equal to 0.
\frac{81}{y}=7z
Variable z cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by z.
7z=\frac{81}{y}
Swap sides so that all variable terms are on the left hand side.
7zy=81
Multiply both sides of the equation by y.
7yz=81
The equation is in standard form.
\frac{7yz}{7y}=\frac{81}{7y}
Divide both sides by 7y.
z=\frac{81}{7y}
Dividing by 7y undoes the multiplication by 7y.
z=\frac{81}{7y}\text{, }z\neq 0
Variable z cannot be equal to 0.
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