Solve 80x+100(60-x)leq5200

$$80x+100(60-x) \leq 5200$$

Solve for x

$$x\geq 40$$

Solution Steps

Use the distributive property to multiply 100 by 60-x.

$$80x+6000-100x\leq 5200$$

Combine 80x and -100x to get -20x.

$$-20x+6000\leq 5200$$

Subtract 6000 from both sides.

$$-20x\leq 5200-6000$$

Subtract 6000 from 5200 to get -800.

$$-20x\leq -800$$

Divide both sides by -20. Since -20 is negative, the inequality direction is changed.

$$x\geq \frac{-800}{-20}$$

Divide -800 by -20 to get 40.

$$x\geq 40$$