Solve 80+40sqrt{2}=5+5+5sqrt{2}*x

$$80+40 \sqrt{ 2 } =5+5+5 \sqrt{ 2 } \times x$$

Solve for x

$$x=7\sqrt{2}+8\approx 17.899494937$$

Steps for Solving Linear Equation

Add 5 and 5 to get 10.

$$80+40\sqrt{2}=10+5\sqrt{2}x$$

Swap sides so that all variable terms are on the left hand side.

$$10+5\sqrt{2}x=80+40\sqrt{2}$$

Subtract 10 from both sides.

$$5\sqrt{2}x=80+40\sqrt{2}-10$$

Subtract 10 from 80 to get 70.

$$5\sqrt{2}x=70+40\sqrt{2}$$

The equation is in standard form.

$$5\sqrt{2}x=40\sqrt{2}+70$$

Divide both sides by 5\sqrt{2}.

$$\frac{5\sqrt{2}x}{5\sqrt{2}}=\frac{40\sqrt{2}+70}{5\sqrt{2}}$$

Dividing by 5\sqrt{2} undoes the multiplication by 5\sqrt{2}.

$$x=\frac{40\sqrt{2}+70}{5\sqrt{2}}$$

Divide 70+40\sqrt{2} by 5\sqrt{2}.

$$x=7\sqrt{2}+8$$